Question

find the zeroes of quadratic polynomial x2-(root 2x+1)x+root2.also find the relationsbip between their coefficients and zeroes​

Answer 1

Answer:

Hope this helps. Help me get the brainless answer. (❁´◡`❁)

Step-by-step explanation:

x2 - (root2 + 1) + root2

= x2 - root2x - 1x + root2

= x ( x - root2) - 1 ( x - root2)

= ( x - 1 ) ( x - root2 )

Thus, x = 1, and x = root2

Now,

Let x = 1 be alpha. Therefore, alpha = 1

Let x = root2 be beta. Thus, beta = root2

Now,

Alpha + beta = -coefficient of x / coefficient of x2

Alpha + beta = -b / a

1 + root2 = root2 / 1

Root2 = root2 / 1 = -b/a

Now,

Alpha * beta = c / a

1 * root2 = root2

Root2 = root2 = c/a