Question

find the zeroes of quadratie question

x2 - 2x -8


Please do fast this answer​

Answer 1

Step-by-step explanation:

given that :-

P(x)= x^2-2x-8

=>x^2-4x+2x-8

=>x(x-4)+2(x-4)

=>(x-4)(x+2)

To get zeroes ,write P(X)=0

=>(x-4)=0 or (x+2)=0

x =4 and x= -2

The zeroes are -2 and 4

Answer 2

x=-2 , x=4

x2-4x+2x-8

x(x-4)+2(x-4)=0

x+2=0,x-4=0

......x=-2, x=4