Question

Find the zeroes of quadric equation polynomial 5x2+8x-4

Answer 1

Here is you solution ...

5x2 +8x -4
= 5x2 +10x -2x - 4
= 5x ( x+2) -2 (x+2)
= ( 5x -2) (x+2)

(5x-2) =x= 2/5

(x+2) = x = -2

So , the two zeroes are 2/5 and -2 .

HOPE IT IS HELPFUL...