find the zeroes of quadric polynomials x^2+5x+6
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Answer:
=> x²-5x+6 = 0
=> splitting the middle term,
=> x²-3x-2x+6 = 0
=> x(x-3)-2(x-3) = 0
=> (x-3)(x-2) = 0
x-3 = 0
=> x= 3
x-2 = 0
=> x = 2
Step-by-step explanation:
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