Question

Find the zeroes of root3x^2 +10x+7 root3

Answer 1

Answer:

Given, q(x) = √3x2 + 10x + 7√3 We put q(x) = 0 ⇒ √3x2 + 10x + 7√3 = 0 ⇒ √3x2 + 3x + 7x + 7√3x = 0 ⇒ √3x(x + √3) + 7 (x + √3) = 0 ⇒ (x + √3)(√3x + 7) = 0 This gives us 2 zeros, for x = -√3 and x = -7/√3 Hence, the zeros of the quadratic equation are -√3 and -7/√3. Now, for verification Sum of zeros = – coefficient of x / coefficient of x2 -√3 + (-7/√3) = – (10) /√3 (-3-7)/ √3 = -10/√3 -10/ √3 = -10/√3 Product of roots = constant / coefficient of x2 (-√3) x (-7/√3) = (7√3)/√3 7 = 7 Therefore, the relationship between zeros and their coefficients is verifiedRead more on Sarthaks.com - https://www.sarthaks.com/623540/q-x-3x-2-10x-73.

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