Question

Find the zeroes of root3x^2-2x+6root3​

Answer 1

Step-by-step explanation:

√3 x² + 11 x + 6√3

= √3 x² + 9 x + 2 x + 6√3

= √3 x(x+3√3) + 2(x+3√3)

= (√3 x + 2)(x+3√3)

Then x = -2/√3 and -3√3