Find the zeroes of s2 – 25
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Answer:
(s-5) & s+5) are the zeros of s^2-25
Step-by-step explanation:
Let p(x) be s^2-25
s^2- 5^2 = (s-5) (s+5) by (a-b)(a+b)= a^2-b^2
Thus the zeroes of the given polynomial are s-5 and s+5.
I hope it helps you.
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Explanation:
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