find the zeroes of sqrt3x²-8x+4sqrt3
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Answer:
two zeros are 2/√3 and 2√3
Step-by-step explanation:
√3x² - 8x + 4√3
=> √3x² - 6x - 2x + 4√3 = 0
=> √3x² - 3*2x - 2x + 4√3 = 0
=> √3x² - √3*√3*2x - 2x + 4√3 = 0
=> √3x (x - 2√3) - 2 (x - 2√3) = 0
=> (√3x - 2)(x - 2√3) = 0
=> √3x - 2 = 0 => x = 2/√3
x - 2√3 = 0 => x = 2√3
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