Math, asked by nehadevgoswami123, 10 months ago

find the zeroes of

${4u}^{2} + 8u$

Answers

Answered by brainlygirl87

0

here is the answer ⇑

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Answered by YashChamle

0

Answer:

The roots of 4u²+8u are:

By taking common we get

=> 4u(u+2)

=> u=-2,1/4

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