Question

find the zeroes of $x^{2} - 88x + 125$

Answer 1

Step-by-step explanation:

x²-88x+125

$roots = - {b}^{2} \frac{ + }{} \sqrt{ {b}^{2} } - 4ac \div 2a$

b²-4ac=(-88)²-4(1)(125)

=7744-500

=7244.

x=88+√7244/2

=88+2√1811/2

x=44+√1811

x=44-√1811.

Answer 2

Answer:

answer attached in photo