Question

find the zeroes of th polynomial 4x²-x-4​

Answer 1

Answer:

The zeroth of the polynomial is -4

Step-by-step explanation:

4x²-x-4x⁰

x⁰=1

Answer 2

Answer:

x = 1/8 + $\sqrt{65}$/8

x = 1/8 - $\sqrt{65}$/8

Step-by-step explanation:

4x²-x-4​ = 0

4x/4²-x/4-4/4​ = 0/4

x^2 - (1/4)x - 1 = 0

complete the square

((1/4/4))^2 = 1/64

x^2 - (1/4)x + (1/64)  = 65/64

(x+1/8)^2 = 65/64

x = 1/8 + $\sqrt{65}$/8

x = 1/8 - $\sqrt{65}$/8