Find the zeroes of the 4x^2+12x+9 and also verify the relationship between zeroes and coefficients
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Hi ...here Is your answer
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Answer:
α= -3/2
β= -3/2
Explanation:
⇒ 4x²+12x+9=0
⇒ 4x²+6x+6x+9=0
⇒ 2x(2x+3)+3(2x+3)
⇒ (2x+3)(2x+3)
∴ 2x+3=0
∴ x=-3/2,-3/2
∴ α+β=-3/2+(-3/2)=-3/2-3/2=-6/2=-3=-b/a
∴ α×β=-3/2(-3/2=9/4=c/a
hence, α+β=-b/a and α×β=c/a
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