Math, asked by rupalijais9302, 10 months ago

Find the zeroes of the codratic polynomial 3x square minus 3 root 3x +2

Answers

Answered by Shahoodalam
0

3x {}^{2}  - 3 \sqrt{3x}  + 2 = 0 \\ 3x {}^{2}  - 2 \sqrt{3x}  -  \sqrt{3x}  + 2 = 0 \\  \sqrt{3x} ( \sqrt{3} x - 2) - 1( \sqrt{3x}  - 2) = 0 \\ ( \sqrt{3x} - 1)( \sqrt{3x}    - 2) = 0 \\  \sqrt{3x}  - 1 = 0 \\  \sqrt{3x}  = 1 \\ x =  \frac{1}{ \sqrt{3} }  \\  \sqrt{3x}  - 2 =0 \\  \sqrt{3x}  = 2 \\ x =  \frac{2}{ \sqrt{3} }  \\

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