Question

find the zeroes of the equation with verification
${ - }^{2} - 2x - 8$
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Answer 1

$\: \: \: \: \: {x}^{2} - 2x - 8 \\ = {x}^{2} + 2x - 4x - 8 \\ = x(x + 2) - 4(x + 2) \\ = (x + 2)(x - 4) \\ \\ x + 2 = 0 \: or \: x - 4 = 0 \\ x = - 2 \: or \: x = 4$

to verify, subsitute -2 first in place of x, solve and you'll get the value of the equation to be zero. then do the same with 4

Answer 2

Answer:

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