Question

find the zeroes of the following & verify the relation with the coefficients.
$x ^{2} - 2 \sqrt{2x}$
$2x {}^{2} - 25$
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Answer 1

Answer:

Step-by-step explanation:

a) x^2 - 2√2x = 0

x^2 = 2√2x

(squaring both sides)

x^4 = 4×2x

x^4 = 8x

x^3 = 8

x = 2

So, zeroes are 0,2

b) 2x^2 -25

2x^2 = 25

X = 5/√2

So, zeroes are 5/√2,0

Hope this helps you