Find the zeroes of the following polynomial.
(a)4t^2-5
(b)2x^2-9
(c)x^3-2x
Proper answer is needed.
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Answers
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(a) 4t² -5 = 0
=> 4t²=5
=> t² = 5/4
=> t = ±✓5/2
(b) 2x²-9=0
=> 2x² = 9
=> x² = 9/2
=> x = ± 3 /✓2
(c) x³ -2x =0
=> x(x²-2) = 0
=> x²-2= 0
=> x² = 2
=> x = ±✓2
=> 4t²=5
=> t² = 5/4
=> t = ±✓5/2
(b) 2x²-9=0
=> 2x² = 9
=> x² = 9/2
=> x = ± 3 /✓2
(c) x³ -2x =0
=> x(x²-2) = 0
=> x²-2= 0
=> x² = 2
=> x = ±✓2
swati104:
Fully right
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