Question

find the zeroes of the following polynomial and verify the relationship between zeroes and coefficients of the polynomial x²+14x+48​

Answer 1

Answer:

${x}^{2}+14x+48\\= {x }^{2} + 8x+6x+48 \\ = x(x + 8) + 6(x + 8) \\ = (x + 6)(x + 8)$

$x = - 6 \: or \: x = - 8$

product of zeroes =c/a

(-6)(-8)=48/1

48=48

sum of zeroes =-b/a

( -6)+(-8)=-14/1

-14=-14