find the zeroes of the following polynomial and verify the realtionship between its zeroes and coefficients.
a) 5x²+12x-9
b) 6x²-7x-3
c) 4x²-11x+6
d) 8x²-2x-3
e) 3x²+5x-12
f) 7x²-8x-12
g) 12x²-5x-2
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Given polynomial is 5x2−8x−4
Here, a=5,b=−8 and c=−4
5x2−8x−4=5x2−10x+2x−4
=5x(x−2)+2(x−2)
=(x−2)(5x+2)
So, the value of 5x2−8x−4 is zero when x=2 or x=5−2
Threrfore , the zeroes of 5x2−8−4 are 2 and 5−2.
Now, sum of zeroes =2+(5−2)=58=a−b
product of zeroes =2×(5−2)=5−4=ac
Hence verified.
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