Question

find the zeroes of the following polynomial and verify the relationship between the zeroes and the coefficients​

Answer 1

Answer:

y^2 -6y +8 = 0

y^2 -2y -4y +8 = 0

y(y-2) -4(y-2) = 0

(y-2)(y-4) = 0

y-2=0. y-4=0

y=2. y=4

2^2-6×2+8=0

4-12+8=0

0=0

4^4-6×4+8=0

16-24+8=0

0=0