Question

find the zeroes of the following polynomial :-
$f(x) = 4 \sqrt{3} x ^{2} + 5x - 2 \sqrt{3}$
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Answer 1

Step-by-step explanation:

I try to slove the question

Answer 2

Answer:

two zeros are x = √3/4 and x = -2/√3

Step-by-step explanation:

p(x) = 4√3x² + 5x - 2√3

=> 4√3x² + 8x - 3x - 2√3 = 0

=> 4√3x² + 8x - √3*√3 x - 2√3 = 0

=> 4x(√3x + 2) - √3(√3x + 2) = 0

=> (4x - √3)(√3x + 2) = 0

=> 4x - √3 = 0 => x = √3/4

=> √3x + 2 = 0 => x = -2/√3