Question

find the zeroes of the following polynomial x2+ x-6​

Answer 1

Answer:

x=2

Step-by-step explanation:

x2+x-6=0

let x = 2

4+3-6=0

Answer 2

${x}^{2} + x - 6 = 0 \\ {x}^{2} + 3x - 2x - 6 = 0 \\ x(x + 3) - 2(x + 3) = 0 \\ (x - 2)(x + 3) = 0$

Therefore, either (x - 2) = 0 or (x + 3) = 0.

So,

$\fbox{x = 2 \:or\: x = -3}$