Question

Find the zeroes of the following polynomials and verify the relationship between the zeroes and coefficients.

2x2+9x+9​

Answer 1

Step-by-step explanation:

2x sq + 9x + 9 = 0

2x sq + 6x + 3x + 9 = 0

2x (x + 3) +3 (x + 3) = 0

(2x + 3) (X + 3) =0

X = -3/2 , X = -3

alpha = -3/2 beta = -3

sum if zeroes (aplha + beta) = -b/a

a = 2, b=9 , C=9

-3/2 + (-3) = -9/2

LHS

-3/2 + (-3)

-3/2 -3/1

-3-6/2

-9/2

RHS

-9/2

LHS = RHS

product if zeroes = alpha × beta = C/a

(-3/2) × (-3) = 9/2

LHS

9/2

RHS

9/2

LHS = RHS

HENCE PROOVED

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