Find the zeroes of the following product 3x^2-x-4
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✧ 3x²-x-4
=>3x²+4x-3x-4
=>x(3x+4)-1(3x+4)
=>(3x+4)(x-1)
Answered by
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Answer:zeroes 4/3,-1
Step-by-step explanation:
3x^2-x-4=0
3x^2+3x-4x-4=0
3x (x+1)-4 (x+1)=0
(3x-4)(x+1)=0
3x=4,x=-1
X=4/3,-1
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