Question

find the zeroes of the following qhadratic and verify the rekationship x2-9​

Answer 1

Answer:

Step-by-step explanation:

X2-9=0

x2=9

x=±3

x=3,-3

Answer 2

${\huge{\pink{\underline{\underline{\purple{\mathbb{\bold{\mathcal{AnSwEr..}}}}}}}}}$

${\large{\blue{\bold{\underline{Given:-}}}}}$

$\implies {x}^{2} - 9$

${\large{\blue{\bold{\underline{So\:To\:Find\:Zeroes:-}}}}}$

$\implies {x}^{2} - 9 = 0 \\ \\ \implies {x}^{2} = 9 \\ \\ \implies {x}^{2} = \frac{ + }{ } (3) {}^{2} \\ \\ \implies \: x = + 3 \: \: or \: \: x = - 3$

☆ Therefore the required zeroes are ${\huge{\pink{\underline{\underline{\mathbb{\bold{3\:And\:-3.}}}}}}}}$

${\large{\blue{\bold{\underline{Verification:-}}}}}$

☆ The given equation can be written as:-

▪︎ x²-0x-9 = 0.

${\large{\orange{\bold{\underline{Sum\:Of\:Zeroes:-}}}}}$

$= \frac{ - b}{a} \\ \\ = \frac{ - ( - 0)}{1} \\ \\ = \frac{0}{1} = 0 \\ \\ and \\ \\ 3 + ( - 3) \\ \\= 3 - 3 \\ \\ = 0 \\ \\ hence \: \: \: \: \: verified.$

${\large{\orange{\bold{\underline{Product\:Of\:Zeroes:-}}}}}$

$= \frac{c} {a} \\ \\ = \frac{ - 9}{1} \\ \\ = - 9 \\ \\ and \\ \\ 3 \times ( - 3) \\ \\ = - 9 \\ \\ hence \: \: \: \: verified$

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