find the zeroes of the following quadratic Polynomial ② 6t²-7t-3
Answers
Answered by
1
Step-by-step explanation:
6t^2-7t-3=0(given)
6t^2-9t+2t-3(7t=9t-2t)=0
taking common
3t(2t-3)+1(2t-3)=0
(3t+1)+(2t-3)=0
(3t+1)=0
t=-1/3
(2t-3)=0
t=3/2
t=-1/3 or 3/2
Similar questions