Find the zeroes of the following quadratic polynomial and verify the relationship between the zeroes and their coefficients:
(1) 21t2-t-2
(ii) 6y2 - 7y + 2
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Answer:
multiply the eq by 3
21y2-11y-2=0
21y2-14y+3y-2=0
7y(3y-2)+1(3y-2)=0
(7y+1)(3y-2)=0
y=-1/7 and y = 2/3
a=7 b=-11/3 c=-2/3
sum of roots is -1/7+2/3=11/21 =-b/a
product of root=-2/21=c/a
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