Find the zeroes of the following quadratic polynomial and verify the relationship between the zeroes and their coefficients: x^2-2x-8
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Answer:
x²- 2x - 8 = 0
x²- 4x +2x -8 =0
x(x - 4) + 2(x - 4) = 0
x+2 =0 x - 4=0
x =-2 x= 4
Sum of the zeroes = - b/a
= -(-2)/1
= 2
Product of the zeroes = c/a
= -8/1
= -8
I hope it will help you mate!
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