Question

find the zeroes of the following quadratic polynomial and verify the relationship between zeroes and the coefficient :- 5y²+7y​

Answer 1

Step-by-step explanation:

Given Equation is 5y2 + 7y

comparing it to standard form of equation that is ax2+bx+c=0

so. 5y2 + 7y +0=0 now it is in standard form

5y2+7y=0

Taking y common we get

y(5y+7)=0

y=0

and 5y+7=0

5y=-7

y=-7/5

so two roots are 0 and -7/5

now relationship

sum of zeroes=-b/a

0+(-7/5)=-(7)/5

where b =7 and a=5

-7/5=-7/5

now product of zeroes =c/a

0×-7/5=0/5

Here c = 0 after comparing it to standard form of equation and a=5

0=0

Hence,Relationship is verified