Question

find the zeroes of the following quadratic polynomial and verify the relationship between the zeroes and the coefficient (1) t^2-15​

Answer 1

Answer:

Hi mate the step follows like this

Plz mark as brain list answer

T^2-15

T=√15 is alpha,-√15 beta

Alpha+beta = -b/a

√15-√15= -0/1

0=0

Alphabeta =c/a

√15*-√15= 15/1

15=15

Answer 2

Step-by-step explanation:

t^2-15 = (t-√15)(t+√15) = 0

(t-√15)=0

t=√15

(t+√15)=0

t= -√15

Therefore √15 and -√15 are the zeroes of the following quadratic polynomial.

Relationship:-

Sum of zeroes = -b/a

√15+(-√15)= -b/a

√15-√15= -0/1

0=0

Product of zeroes =c/a

√15× (-√15)= -15/1

-15 = -15 (HENCE VERIFIED)

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