Question

find the zeroes of the following quadratic polynomial and verify the relationship between the zeroes and the coefficient. of x2-2x-8​

Answer 1

Answer:

${x}^{2} - 2x - 8 \\ {x}^{2} - 4x + 2x - 8 \\ x(x- 4) + 2(x - 4) \\ (x - 4)(x + 2) \\ either \: x = 4 \: or \: x = - 2$

$verification \\ \alpha + \beta = \frac{ - b}{a} \\ 4 + ( - 2) = \frac{ - ( - 2)}{1} \\ 2 = 2 \\ \alpha \beta = \frac{c}{a} \\ 4( - 2) = \frac{ - 8}{1} \\ - 8 = - 8 \\ 8 = 8 \\ hence \: verified$

Done