Question

find the zeroes of the following quadratic polynomial and verify the relationship between the zeros and the coefficient 2x^2-6x

Answer 1

Answer:

f(x) = 2x2 ˗ 11x + 15 = 2x2 ˗ (6x + 5x) + 15 = 2x2 ˗ 6x ˗ 5x + 15 = 2x (x ˗ 3) ˗ 5 (x ˗ 3) = (2x ˗ 5) (x ˗ 3) ∴ f(x) = 0 ⇒ (2x ˗ 5) (x ˗ 3) = 0 ⇒ 2x ˗ 5= 0 or x ˗ 3 = 0 ⇒ x = 5/ 2 or x = 3 So, the zeroes of f(x) are 5/ 2 and 3.

Step-by-step explanation:

Not sure about this answer

Answer 2

Answer:

The number of the polynomial coefficient is equal to the polynomial degree.

Step-by-step explanation:

Therefore, Number of zeros = 2

Since,

$x {}^{1 + x {}^{1} }$

= x raise to power 2

No of zeros = 2