Question

find the zeroes of the following quadratic polynomial and verify the relationship between the zeroes and the coefficients. x^2-3​

Answer 1

Answer:

Answer:Standard form of a quadratic polynomial: ax^ +bx +c=0

Answer:Standard form of a quadratic polynomial: ax^ +bx +c=0Therefore ,x^+2x-3=0

Answer:Standard form of a quadratic polynomial: ax^ +bx +c=0Therefore ,x^+2x-3=0Now Zeroes of the polynomial:

Answer:Standard form of a quadratic polynomial: ax^ +bx +c=0Therefore ,x^+2x-3=0Now Zeroes of the polynomial: x^+2x-3

Answer:Standard form of a quadratic polynomial: ax^ +bx +c=0Therefore ,x^+2x-3=0Now Zeroes of the polynomial

x^+3x-x-3

x^+3x-x-3X(x+3)-1(x+3)

x^+3x-x-3X(x+3)-1(x+3) (x+3) (X-1)

x^+3x-x-3X(x+3)-1(x+3) (x+3) (X-1)x+3=0 ,X-1=0

x^+3x-x-3X(x+3)-1(x+3) (x+3) (X-1)x+3=0 ,X-1=0X= -3. X=1

x^+3x-x-3X(x+3)-1(x+3) (x+3) (X-1)x+3=0 ,X-1=0X= -3. X=1(-3 ,1) are the two zereos of the required polynomial.

x^+3x-x-3X(x+3)-1(x+3) (x+3) (X-1)x+3=0 ,X-1=0X= -3. X=1(-3 ,1) are the two zereos of the required polynomial.sum of zeroes= -b

x^+3x-x-3X(x+3)-1(x+3) (x+3) (X-1)x+3=0 ,X-1=0X= -3. X=1(-3 ,1) are the two zereos of the required polynomial.sum of zeroes= -b a

x^+3x-x-3X(x+3)-1(x+3) (x+3) (X-1)x+3=0 ,X-1=0X= -3. X=1(-3 ,1) are the two zereos of the required polynomial.sum of zeroes= -b a~3 - 1 = 2

x^+3x-x-3X(x+3)-1(x+3) (x+3) (X-1)x+3=0 ,X-1=0X= -3. X=1(-3 ,1) are the two zereos of the required polynomial.sum of zeroes= -b a~3 - 1 = 2 1

x^+3x-x-3X(x+3)-1(x+3) (x+3) (X-1)x+3=0 ,X-1=0X= -3. X=1(-3 ,1) are the two zereos of the required polynomial.sum of zeroes= -b a~3 - 1 = 2 1 2=2

x^+3x-x-3X(x+3)-1(x+3) (x+3) (X-1)x+3=0 ,X-1=0X= -3. X=1(-3 ,1) are the two zereos of the required polynomial.sum of zeroes= -b a~3 - 1 = 2 1 2=2Product of zeroes= c

x^+3x-x-3X(x+3)-1(x+3) (x+3) (X-1)x+3=0 ,X-1=0X= -3. X=1(-3 ,1) are the two zereos of the required polynomial.sum of zeroes= -b a~3 - 1 = 2 1 2=2Product of zeroes= c a

x^+3x-x-3X(x+3)-1(x+3) (x+3) (X-1)x+3=0 ,X-1=0X= -3. X=1(-3 ,1) are the two zereos of the required polynomial.sum of zeroes= -b a~3 - 1 = 2 1 2=2Product of zeroes= c a-3×1 =-3

x^+3x-x-3X(x+3)-1(x+3) (x+3) (X-1)x+3=0 ,X-1=0X= -3. X=1(-3 ,1) are the two zereos of the required polynomial.sum of zeroes= -b a~3 - 1 = 2 1 2=2Product of zeroes= c a-3×1 =-3 1

-3 =-3

-3 =-3 Hence verified.

-3 =-3 Hence verified.

very much glitch , this app is becoming worse .