Find the zeroes of the following quadratic polynomial and verify the relationship between zeroes and the coefficients 2x²-x-6
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Answer:
2x^2-x-6=0
2x^2-4x+3x-6=0
2x(x-2)+3(x-2)=0
(2x+3)(x-2)=0
x=-3/2 or x=2
Step-by-step explanation:
sum of zeros: -b/a = -(-1)/2 = 1/2
product of zeros: c/a = -6/2 = -3
Answered by
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Answer:
2x²-x-6 = 0
2x²-4x+3x-6 =0
2x(x-2)+3(x-2) = 0
(2x+3)(x-2) = 0
x = 2,-3/2
sum of zeros = -1/2
product of zeros = -6/2
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