Question

Find the zeroes of the following quadratic polynomial and verify the relationship between the zeroes and the coefficient
(I) x2-2x-8
(ii) 4s-4s+1​

Answer 1

Answer:

(i) x

2

−2x−8

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Answer 2

Step-by-step explanation:

☠️Answer☠️By splitting the middle term, we get f(x) = x2 – 4x + 2x – 8

[∵ – 2 = 2 – 4 and 2×4 = 8]

= x(x – 4) + 2(x – 4) = (x + 2) (x – 4)

On putting f(x) = 0,

we get (x + 2) (x – 4) = 0

⇒ x + 2 = 0 or x – 4 = 0

⇒x = – 2 or x = 4

Thus, the zeroes of the given polynomial x2 – 2x – 8 are – 2 and 4

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