Question

Find the zeroes of the following quadratic polynomial and verify the relationship between the zeroes and the coefficients: 6 ^2 − 5 − 1​

Answer 1

Answer:

Solution

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(i) x

2

−2x−8

Factorize the equation, we get (x+2)(x−4)

So, the value of x

2

−2x−8 is zero when x+2=0,x−4=0, i.e., when x=−2 or x=4.

Therefore, the zeros of x

2

−2x−8 are -2 and 4.

Now,

⇒Sum of zeroes =−2+4=2=−

1

2

=−

Coefficient of x

2

Coefficient of x

⇒Product of zeros =(−2)×(4)=−8 =

1

−8

=

Coefficient of x

2

Constant term