Find the zeroes of the following quadratic polynomial s and verify their relationship with coefficient of the poly nomial
x²-3x-28
Answers
Answered by
1
Answer:
x = -4 or x=7
Step-by-step explanation:
x²-3x-28 = x²-7x+4x-28 = x(x-7)+4(x-7) = (x+4)(x-7)
Therefore x = -4 and x=7
Sum of roots = -b/a = 3
which is equal to -4+7 = 2
Product of roots = c/a = -28
which is equal to -4*7 = -28
Please mark as brainliest answer
Answered by
1
Answer:
f(x) = x² - 3x - 28
To find zero
put f(x) = 0
x² - 3x - 28 = 0
x² - 7x + 4x - 28 = 0
x ( x - 7 ) + 4 (x - 7 ) = 0
( x - 7 )( x + 4 ) = 0
x = 7 & -4
let α = 7 and β = -4
Now to verify the relation
sum of zeroes = α + β = 7 + (-4) = 3
Product of zeroes = α . β = 7 × (-4) = -28
Hence proved
Similar questions