Question

Find the zeroes of the following quadratic
polynomial. x2-5x+6​

Answer 1

Answer:

x²-5x+6

➡️ x²-2x-3x+6

➡️ x(x-2)-3(x-2)

➡️ (x-3)(x-2)

x=3 and x=2

hope it helps you.....✌✌

Answer 2

Answer:

$\large\boxed{\sf{2\;and\;3}}$

Step-by-step explanation:

Given a quadratic polynomial such that,

${x}^{2} - 5x + 6$

To find the roots.

First of all, make this a quadratic equation,

For this, equate the polynomial to zero.

Therefore, we will get,

$= > {x}^{2} - 5x + 6 = 0$

Now, factorise the Equation,

Therefore, we will get,

By middle term splitting method,

$= > {x}^{2} - 2x - 3x + 6 = 0$

Now, taking out the common terms, we get,

$= > x(x - 2) - 3(x - 2) = 0 \\ \\ = > (x - 2)(x - 3) = 0$

Now, we have two cases.

Case 1.

When x - 2 = 0

=> x = 2

Case 2.

When x - 3 = 0

=> x = 3

Hence, roots are 2 and 3.