Question

find the zeroes of the following quadratic polynomial x²+x–12 and verify the relationship between the zeroes and their coefficients ​

Answer 1

MARK AS BRAINLIST ANSWER

Answer 2

Answer:

$\large\boxed{\sf{-4\;\;and\;\;3}}$

Step-by-step explanation:

Given a quadratic polynomial,

${x}^{2} + x - 12$

Here, we have,

• a = 1
• b = 1
• c = -12

To find its zeroes, let's equate the polynomial to 0.

Therefore, we will get,

$= > {x}^{2} + x - 12 = 0$

Now, factorising the above equation, we get,

$= > {x}^{2} + 4x - 3x - 12 = 0 \\ \\ = > x(x + 4) - 3(x + 4) = 0 \\ \\ = > (x + 4)(x - 3) = 0 \\ \\ = > x = - 4 \: \: \: \: \: and \: \: \: \: 3$

Therefore, the zeroes are -4 and 3.

Verification:-

We know that,

Sum of zeroes = -b/a = -1/1 = -1

=> -4 + 3 = -1

And,

Product of zeroes = c/a = -12/1 = -12

=> -4 × 3 = -12

Hence, verified.