Question

Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients.
$6x { }^{2} - 3 - 7x$
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Answer 1

Answer:

x= -1/3 or x = 3/2

Explanation:

6x^2-7x-3

= 6x^2 - (9-2)x - 3

= 6x^2 - 9x +2x - 3

= 3x(2x-3)+1(2x-3)

= (2x-3)(3x+1)

so, the zeros are x= -1/3 or x= 3/2

Answer 2

Explanation:

Heya there!

$6 {x}^{2} - 7x - 3$

$using \: formula \: method$

$\frac{ - b + \: or \: - \sqrt{ {b}^{2} - 4ac } }{2a}$

$\frac{7 + \: or \: - \sqrt{ {7}^{2} + 4(18)} }{12}$

$\frac{7 + \: or \: - \: 11}{12}$

$\frac{7 + 11}{12} \: \: \: \: or \: \: \: \: \: \: \frac{7 - 11}{12}$

$\frac{19}{12} \: \: \: \: or \: \: \: \: \frac{ - 1}{4}$

$hepe \: it \: helps \: you.......$