Question

find the zeroes of the following quadratic polynomials and verify the relationship betwee
the zeroes and the coefficients x2-2x -8​

Answer 1

Step-by-step explanation:

x^2-2x-8=0

x^2-4x+2x-8=0

x(x-4)+2(x-4)=0

(x+2)(x-4)=0

x=(-2) or x=4

Answer 2

Answer :

x² - 2x - 8 = 0

x² - 4x + 2x - 8 = 0

x(x - 4) + 2(x - 4) =0

(x + 2)(x - 4) = 0

x = -2 or x = 4

Verification :

Sum of roots = -b/a

- 2 + (4) = -(-2)/1

2 = 2

Product of roots = c/a

-2 × 4 = -8/1

-8 = -8