Question

Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients : 4u2+8u

Answer 1

Answer:

4u2+8u=0

4u(u+2)=0

4u=0, u+2=0

u=o, u=-2

alpha=0, beta=-2

sum of zeroes=-b/a

0+(-2)=-8/4

-2=-2 LHS=RHS

product of zeroes=c/a

o into -2=o/4

0=0 LHS=RHS

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Step-by-step explanation:

Answer 2

Step-by-step explanation:

4u2+8u=0

4u(u+2)=0

u(u+2)=0/4

u(u+2)=0

So, u=0,(-2)

Therefore,