Question

Find the zeroes of the following quadratic polynomials and verify the relationship between
the zeroes and the coefficients.

1. 6x² - 3 - 7x ​

Answer 1

Answer:

6.4x

think about it because I am not sure of my answer

Answer 2

Step-by-step explanation:

f(x)= 6x²-3-7x

=6x² -7x - 3

= 6x² + 9x - 2x -3

= 3x(2x+ 3) - (2x+3)

= (2x+3)(3x-1)

2x+3= 0

2x= -3

x=-3/2

alpha =-3/2

3x-1=0

3x= 1

x=1/3

beta = 1/3

in given f(x) , a=6,b=-7, c=-3

verification

sum of zeroes = -coefficient of x / coefficient of x²

alpha + beta = - b/a

-3/2+ 1/3 = -(-7)/6

7/6. = 7/6

product of zeroes = constant / coefficient of x ²

alpha * beta = c/a

-3/2 * 1/3 = -3/6

-1/2. = -1/2