Question

.. Find the zeroes of the following quadratic polynomials and verify the relationship between the
zeroes and the coefficients.
a) x2 - 2x -8
​

Answer 1

Step-by-step explanation:

x² - 2x - 8

x² - 4x +2x - 8

x (x - 4) +2 (x - 4)

(x - 4) (x +2)

x - 4 =0 or x +2 =0

x = 0 + 4 x = 0 - 2

x = 4 x = - 2

Answer 2

Firstly, we have to Factories the Quadratic equations.

→ x² – 2x – 8

→ x²– 4x+2x–8

→ x(x–4) + 2(x–4)

→ (x-4) (x+2)

→ x = 4, –2

So, zeroes of polynomial equation x²–2x–8 are (4, -2).

» Sum of zeroes of the polynomial,

→ 4 – 2 = –b/a

→ 2 = –(-2)/1

→ 2 = 2

» Product of zeroes of the Polynomial,

→ 4×(-2) = c/a

→ –8 = –8/1

→ –8 = –8

Hence, VERIFIED ||