Question

Find the zeroes of the following quadratic polynomials and verify the relationship
between the zeroes and the coefficients.
(iii) 6x square- 3 - 7x​

Answer 1

Answer:

(iii) 6x

2

−3−7x

Factorize the equation, we get (3x+1)(2x−3)

So, the value of 6x

2

−3−7x is zero when 3x+1=0,2x−3=0, i.e., when x=−

3

1

or x=

2

3

.

Therefore, the zeros of 6x

2

−3−7x are −

3

1

and

2

3

.

Now,

⇒Sum of zeroes = −

3

1

+

2

3

=

6

7

=−

6

−7

=−

Coefficient of x

2

Coefficient of x

⇒Product of zeros = −

3

1

×

2

3

=−

2

1

=

6

−3

=

2

−1

=

Coefficient of x

2

Constant term

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

6x^2 -3 - 7x

change into quadratic equation

6x^2 -7x -3

middle term splitting

6x^2- 9x + 2x- 3

(3x +1) (2x -3 )

3x + 1 = 0. 2x -3 = 0

3x= -1/3 2x = 3

X= -1/3 x=3/2

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