Question

find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients of the polynomial: x² - 81​

Answer 1

Answer:

$question - \ \\ {x}^{2} - 81 \\ =( x - 9)(x + 9) \: \: \: \\ \alpha = 9 \: \beta = - 9 \\ \alpha + \beta = 9 + ( - 9) \\ = 0 \\ = - coeff \: of \: x \div coeff \: of \: {x}^{2} \\ \alpha \beta = 9 \times - 9 \\ = - 81 \\ = contant \: term \div coeff \: of \: {x}^{2}$

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