Question

Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients: 2x+3x+4​

Answer 1

Answer:We have p(x) = x2 – 2x – 8

= x2 + 2x – 4x – 8 = x (x + 2) – 4 (x + 2)

= (x – 4) (x + 2)

For p(x) = 0, we have

(x – 4) (x + 2) = 0

Either x – 4 = 0 ⇒ x = 4

or x + 2 = 0 ⇒ x = – 2

∴ The zeroes of x2 2x – 8 are 4 and –2.

Now, sum of the zeroes

Step-by-step explanation:

Answer 2

Answer:

p(x)=0

2x+3x+4=0

5x+4=0

5x= -4

x= -4/5

Step-by-step explanation:

This is a correct answer