Find the zeroes of the following quadratic polynomials and verify the relationship between the zeros and the coefficients. (iv) 4u2 + 8u
Answers
Answered by
6
We have,
p(u)=4u^2+8u
=4u(u+2)
p(u)=0
4u(u+2)=0
either 4u=0 or u+2=0
if 4u=0, then,u=0
if (u+2)=0 then,, u=-2
So, the zeros of p(u) are 0 and -2
We can write the above polynomial as
p(u)=4^2+8u+0u
Sum of the zeros=0+(-2)=-2=-(coefficient of u)/(coefficient of u^2)
product of zeros=0×-2=0=constant term/coefficient of u^2
p(u)=4u^2+8u
=4u(u+2)
p(u)=0
4u(u+2)=0
either 4u=0 or u+2=0
if 4u=0, then,u=0
if (u+2)=0 then,, u=-2
So, the zeros of p(u) are 0 and -2
We can write the above polynomial as
p(u)=4^2+8u+0u
Sum of the zeros=0+(-2)=-2=-(coefficient of u)/(coefficient of u^2)
product of zeros=0×-2=0=constant term/coefficient of u^2
Similar questions