Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficient.x square–5x
Answers
Step-by-step explanation:
Given :-
x²-5x
To find :-
Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients ?
Solution :-
Finding zeroes :-
Given Quadratic Polynomial is x²-5x
Let P(x) = x²-5x
=> P(x) = x(x-5)
To get zeroes we write P(x) = 0
=> x(x-5) = 0
=> x = 0 or x-5 = 0
=> x = 0 or x = 5
Zeroes are 0 and 5
Relationship between the zeroes and the coefficients:-
The zeroes are 0 and 5
Let α = 0 and β = 5
On Comparing P(x) with the standard quadratic Polynomial ax²+bx+c
We have
a = 1
b = -5
c = 0
i) Sum of the zeroes = α+β
=> α+β
= 0+(-5)
= -5
= -5/1
= - ( Coefficient of x )/Coefficient of x²
= -b/a
α+ β = -b/a
ii) Product of the zeroes = αβ
=> 0/1
= 0
= Constant term/ Coefficient of x²
= c/a
αβ = c/a
we get
Sum of the zeroes = -b/a
Product of the zeroes = c/a
Verified the relationship between the zeroes and the coefficients of P(x).
Answer:-
The zeroes are 0 and -5
Used formulae:-
- The standard quadratic Polynomial ax²+bx+c
- Sum of the zeroes = -b/a
- Product of the zeroes = c/a