Math, asked by trishanthmani131, 1 month ago

find the zeroes of the following quadratic Polynomials and verify the relationship between the zeroes and the coefficient (1) x^2 -2x -8​

Answers

Answered by ayushi9633
1

Step-by-step explanation:

x2 - 2x - 8 = 0

x2 - 4x + 2x - 8 = 0

x(x-4) +2(x-4) = 0

(x+2)(x-4) = 0

The zeroes of the given quadratic polynomial are -2 and 4

VERSIFICATION:

sum of root ;

α

α+

α+β

α+β=

α+β=−

α+β=−2

α+β=−2+

α+β=−2+4

α+β=−2+4=

α+β=−2+4=2

c

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coeff

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coefficient

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coefficient of

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coefficient of xcoefficient of

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coefficient of xcoefficient of x2

coefficient of xcoefficient of x2=

coefficient of xcoefficient of x2=−

coefficient of xcoefficient of x2=−−

coefficient of xcoefficient of x2=−−2

coefficient of xcoefficient of x2=−−21

coefficient of xcoefficient of x2=−−21=

coefficient of xcoefficient of x2=−−21=2

coefficient of xcoefficient of x2=−−21=2=

coefficient of xcoefficient of x2=−−21=2=α

coefficient of xcoefficient of x2=−−21=2=α+

coefficient of xcoefficient of x2=−−21=2=α+β

α

αβ

αβ=

αβ=−

αβ=−2

αβ=−2×

αβ=−2×4

αβ=−2×4=

αβ=−2×4=−

αβ=−2×4=−8

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