"Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients.
[tex]
(i) x^{2} - 2x - 8
(ii) 4s^{2} – 4s + 1
(iii) 6x^{2} – 3 – 7x
(iv) 4u^{2} + 8u
(v) t^{2} – 15
(vi) 3x^{2} – x – 4[/tex]"
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Let x^2-2x-8 =0
Product =-8
Sum=-2
No.= -4,2
X^2-2x-8=0
X^2-4x+2x-8=0
X(x-4)+2(x-4)=0
(X+2)(x-4)=0
Therefore x= -2,4
yash111197:
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